f(x)=a(x^2-4x-5)(x-(4+4i))(x(4i-4i))

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Solution for f(x)=a(x^2-4x-5)(x-(4+4i))(x(4i-4i)) equation: 


Simplifying
f(x) = a(x2 + -4x + -5)(x + -1(4 + 4i))(x(4i + -4i))

Multiply f * x
fx = a(x2 + -4x + -5)(x + -1(4 + 4i))(x(4i + -4i))

Reorder the terms:
fx = a(-5 + -4x + x2)(x + -1(4 + 4i))(x(4i + -4i))
fx = a(-5 + -4x + x2)(x + (4 * -1 + 4i * -1))(x(4i + -4i))
fx = a(-5 + -4x + x2)(x + (-4 + -4i))(x(4i + -4i))

Reorder the terms:
fx = a(-5 + -4x + x2)(-4 + -4i + x)(x(4i + -4i))

Combine like terms: 4i + -4i = 0
fx = a(-5 + -4x + x2)(-4 + -4i + x)(x(0))

Reorder the terms for easier multiplication:
fx = a(-5 + -4x + x2)(-4 + -4i + x)(0x)

Anything times zero is zero.
fx = a(-5 + -4x + x2)(-4 + -4i + x)(0x)

Reorder the terms for easier multiplication:
fx = 0a(-5 + -4x + x2)(-4 + -4i + x)

Anything times zero is zero.
fx = 0a(-5 + -4x + x2)(-4 + -4i + x)

Solving
fx = 0

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Simplifying
fx = 0

The solution to this equation could not be determined.

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